Base | Representation |
---|---|
bin | 1010010100000111000… |
… | …01110101111001001111 |
3 | 1020212202022211210011112 |
4 | 11022003201311321033 |
5 | 21301244331130241 |
6 | 430450101242235 |
7 | 34414133224451 |
oct | 5120341657117 |
9 | 1225668753145 |
10 | 354394005071 |
11 | 1273301a43a7 |
12 | 58825a0337b |
13 | 2755b012a22 |
14 | 1321d26a2d1 |
15 | 9342ba61eb |
hex | 5283875e4f |
354394005071 has 2 divisors, whose sum is σ = 354394005072. Its totient is φ = 354394005070.
The previous prime is 354394005019. The next prime is 354394005103. The reversal of 354394005071 is 170500493453.
It is a strong prime.
It is an emirp because it is prime and its reverse (170500493453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 354394005071 - 210 = 354394004047 is a prime.
It is a super-2 number, since 2×3543940050712 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (354394005011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177197002535 + 177197002536.
It is an arithmetic number, because the mean of its divisors is an integer number (177197002536).
Almost surely, 2354394005071 is an apocalyptic number.
354394005071 is a deficient number, since it is larger than the sum of its proper divisors (1).
354394005071 is an equidigital number, since it uses as much as digits as its factorization.
354394005071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 41.
The spelling of 354394005071 in words is "three hundred fifty-four billion, three hundred ninety-four million, five thousand, seventy-one".
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