Base | Representation |
---|---|
bin | 1010010100000111000… |
… | …01110101111001101111 |
3 | 1020212202022211210012201 |
4 | 11022003201311321233 |
5 | 21301244331130403 |
6 | 430450101242331 |
7 | 34414133224525 |
oct | 5120341657157 |
9 | 1225668753181 |
10 | 354394005103 |
11 | 1273301a4426 |
12 | 58825a033a7 |
13 | 2755b012a48 |
14 | 1321d26a315 |
15 | 9342ba621d |
hex | 5283875e6f |
354394005103 has 2 divisors, whose sum is σ = 354394005104. Its totient is φ = 354394005102.
The previous prime is 354394005071. The next prime is 354394005137. The reversal of 354394005103 is 301500493453.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 354394005103 - 25 = 354394005071 is a prime.
It is a super-2 number, since 2×3543940051032 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (354394005403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177197002551 + 177197002552.
It is an arithmetic number, because the mean of its divisors is an integer number (177197002552).
Almost surely, 2354394005103 is an apocalyptic number.
354394005103 is a deficient number, since it is larger than the sum of its proper divisors (1).
354394005103 is an equidigital number, since it uses as much as digits as its factorization.
354394005103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 354394005103 its reverse (301500493453), we get a palindrome (655894498556).
The spelling of 354394005103 in words is "three hundred fifty-four billion, three hundred ninety-four million, five thousand, one hundred three".
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