Base | Representation |
---|---|
bin | 110011100101110110011… |
… | …110001000101011001101 |
3 | 110112221010112110122022002 |
4 | 303211312132020223031 |
5 | 431041321410134131 |
6 | 11312412114402045 |
7 | 514066502430425 |
oct | 63456636105315 |
9 | 13487115418262 |
10 | 3545335630541 |
11 | 114762859a431 |
12 | 493139890325 |
13 | 1c9429283663 |
14 | c3849195485 |
15 | 623504b16cb |
hex | 33976788acd |
3545335630541 has 2 divisors, whose sum is σ = 3545335630542. Its totient is φ = 3545335630540.
The previous prime is 3545335630387. The next prime is 3545335630567. The reversal of 3545335630541 is 1450365335453.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3148619569225 + 396716061316 = 1774435^2 + 629854^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3545335630541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3545335638541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772667815270 + 1772667815271.
It is an arithmetic number, because the mean of its divisors is an integer number (1772667815271).
Almost surely, 23545335630541 is an apocalyptic number.
It is an amenable number.
3545335630541 is a deficient number, since it is larger than the sum of its proper divisors (1).
3545335630541 is an equidigital number, since it uses as much as digits as its factorization.
3545335630541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4860000, while the sum is 47.
The spelling of 3545335630541 in words is "three trillion, five hundred forty-five billion, three hundred thirty-five million, six hundred thirty thousand, five hundred forty-one".
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