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35454312041 is a prime number
BaseRepresentation
bin100001000001001111…
…011101111001101001
310101111212112122220012
4201001033131321221
51040102300441131
624142032541305
72363406452141
oct410117357151
9111455478805
1035454312041
1114044042435
126a556b1835
1334603a0285
141a049ab921
15dc78c152b
hex8413dde69

35454312041 has 2 divisors, whose sum is σ = 35454312042. Its totient is φ = 35454312040.

The previous prime is 35454312031. The next prime is 35454312043. The reversal of 35454312041 is 14021345453.

35454312041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32517105625 + 2937206416 = 180325^2 + 54196^2 .

It is a cyclic number.

It is not a de Polignac number, because 35454312041 - 226 = 35387203177 is a prime.

Together with 35454312043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 35454311989 and 35454312007.

It is not a weakly prime, because it can be changed into another prime (35454312043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17727156020 + 17727156021.

It is an arithmetic number, because the mean of its divisors is an integer number (17727156021).

Almost surely, 235454312041 is an apocalyptic number.

It is an amenable number.

35454312041 is a deficient number, since it is larger than the sum of its proper divisors (1).

35454312041 is an equidigital number, since it uses as much as digits as its factorization.

35454312041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 35454312041 its reverse (14021345453), we get a palindrome (49475657494).

The spelling of 35454312041 in words is "thirty-five billion, four hundred fifty-four million, three hundred twelve thousand, forty-one".