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355012121 is a prime number
BaseRepresentation
bin10101001010010…
…000111000011001
3220202000111002002
4111022100320121
51211340341441
655121050345
711540360522
oct2512207031
9822014062
10355012121
11172438952
129aa869b5
135871c659
1435213849
1521278b9b
hex15290e19

355012121 has 2 divisors, whose sum is σ = 355012122. Its totient is φ = 355012120.

The previous prime is 355012111. The next prime is 355012123. The reversal of 355012121 is 121210553.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 272910400 + 82101721 = 16520^2 + 9061^2 .

It is an emirp because it is prime and its reverse (121210553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 355012121 - 214 = 354995737 is a prime.

Together with 355012123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 355012093 and 355012102.

It is not a weakly prime, because it can be changed into another prime (355012123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177506060 + 177506061.

It is an arithmetic number, because the mean of its divisors is an integer number (177506061).

Almost surely, 2355012121 is an apocalyptic number.

It is an amenable number.

355012121 is a deficient number, since it is larger than the sum of its proper divisors (1).

355012121 is an equidigital number, since it uses as much as digits as its factorization.

355012121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 300, while the sum is 20.

The square root of 355012121 is about 18841.7653366132. The cubic root of 355012121 is about 708.0779337163.

Adding to 355012121 its reverse (121210553), we get a palindrome (476222674).

The spelling of 355012121 in words is "three hundred fifty-five million, twelve thousand, one hundred twenty-one".