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355014121433401 is a prime number
BaseRepresentation
bin101000010111000100010101…
…0100110010010100100111001
31201120000000111112012010022001
41100232020222212102210321
5333013022410041332101
63255015122541301001
7134530631611163203
oct12056105246224471
91646000445163261
10355014121433401
11a3133709393a91
1233998146b64761
13123128c37073b1
146394abd06d773
152b09aea80d901
hex142e22a992939

355014121433401 has 2 divisors, whose sum is σ = 355014121433402. Its totient is φ = 355014121433400.

The previous prime is 355014121433399. The next prime is 355014121433479. The reversal of 355014121433401 is 104334121410553.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 354912630765625 + 101490667776 = 18839125^2 + 318576^2 .

It is a cyclic number.

It is not a de Polignac number, because 355014121433401 - 21 = 355014121433399 is a prime.

Together with 355014121433399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (355014121433701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177507060716700 + 177507060716701.

It is an arithmetic number, because the mean of its divisors is an integer number (177507060716701).

Almost surely, 2355014121433401 is an apocalyptic number.

It is an amenable number.

355014121433401 is a deficient number, since it is larger than the sum of its proper divisors (1).

355014121433401 is an equidigital number, since it uses as much as digits as its factorization.

355014121433401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 355014121433401 its reverse (104334121410553), we get a palindrome (459348242843954).

The spelling of 355014121433401 in words is "three hundred fifty-five trillion, fourteen billion, one hundred twenty-one million, four hundred thirty-three thousand, four hundred one".