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35513440134149 is a prime number
BaseRepresentation
bin10000001001100100111011…
…11110111110010000000101
311122202001101201000011011002
420010302131332332100011
514123323011133243044
6203310352115423045
710323522103314425
oct1004623576762005
9148661351004132
1035513440134149
111035219013879a
123b968ab2b4a85
1316a7b97c77183
148aac06d32485
15418bbd02074e
hex204c9dfbe405

35513440134149 has 2 divisors, whose sum is σ = 35513440134150. Its totient is φ = 35513440134148.

The previous prime is 35513440134077. The next prime is 35513440134169. The reversal of 35513440134149 is 94143104431553.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35224308090049 + 289132044100 = 5935007^2 + 537710^2 .

It is an emirp because it is prime and its reverse (94143104431553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35513440134149 - 212 = 35513440130053 is a prime.

It is a super-2 number, since 2×355134401341492 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35513440134169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17756720067074 + 17756720067075.

It is an arithmetic number, because the mean of its divisors is an integer number (17756720067075).

Almost surely, 235513440134149 is an apocalyptic number.

It is an amenable number.

35513440134149 is a deficient number, since it is larger than the sum of its proper divisors (1).

35513440134149 is an equidigital number, since it uses as much as digits as its factorization.

35513440134149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 47.

The spelling of 35513440134149 in words is "thirty-five trillion, five hundred thirteen billion, four hundred forty million, one hundred thirty-four thousand, one hundred forty-nine".