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3554113002134 = 25930119601713
BaseRepresentation
bin110011101110000001101…
…001001001101010010110
3110120202210020122022112212
4303232001221021222112
5431212310412032014
611320423104113422
7514530143030162
oct63560151115226
913522706568485
103554113002134
111150322152642
12494989305872
131ca1c7885a66
14c403cbb7ca2
15626b5d6423e
hex33b81a49a96

3554113002134 has 8 divisors (see below), whose sum is σ = 5421528308520. Its totient is φ = 1746936899296.

The previous prime is 3554113002133. The next prime is 3554113002157. The reversal of 3554113002134 is 4312003114553.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 3554113002134.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3554113002133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15059800739 + ... + 15059800974.

It is an arithmetic number, because the mean of its divisors is an integer number (677691038565).

Almost surely, 23554113002134 is an apocalyptic number.

3554113002134 is a deficient number, since it is larger than the sum of its proper divisors (1867415306386).

3554113002134 is a wasteful number, since it uses less digits than its factorization.

3554113002134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30119601774.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 3554113002134 its reverse (4312003114553), we get a palindrome (7866116116687).

The spelling of 3554113002134 in words is "three trillion, five hundred fifty-four billion, one hundred thirteen million, two thousand, one hundred thirty-four".

Divisors: 1 2 59 118 30119601713 60239203426 1777056501067 3554113002134