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3556040087 is a prime number
BaseRepresentation
bin1101001111110100…
…1101110110010111
3100011211022112221102
43103331031312113
524240321240322
61344510140315
7154056561545
oct32375156627
910154275842
103556040087
111565323606
12832ab169b
1344895b042
1425a3c8d95
1515c2cb792
hexd3f4dd97

3556040087 has 2 divisors, whose sum is σ = 3556040088. Its totient is φ = 3556040086.

The previous prime is 3556040023. The next prime is 3556040113. The reversal of 3556040087 is 7800406553.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3556040087 - 26 = 3556040023 is a prime.

It is a super-3 number, since 3×35560400873 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 3556040087.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3556040387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1778020043 + 1778020044.

It is an arithmetic number, because the mean of its divisors is an integer number (1778020044).

Almost surely, 23556040087 is an apocalyptic number.

3556040087 is a deficient number, since it is larger than the sum of its proper divisors (1).

3556040087 is an equidigital number, since it uses as much as digits as its factorization.

3556040087 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 38.

The square root of 3556040087 is about 59632.5421812621. The cubic root of 3556040087 is about 1526.3549848443.

The spelling of 3556040087 in words is "three billion, five hundred fifty-six million, forty thousand, eighty-seven".