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36531814751981 is a prime number
BaseRepresentation
bin10000100111001101110011…
…10101110101111011101101
311210100101222222111212201022
420103212321311311323231
514242014124034030411
6205410252314023525
710460223265614023
oct1023467165657355
9153311888455638
1036531814751981
1110705068054a5a
12412013aa17ba5
13174cc20c68733
14904213840713
1543542298cedb
hex2139b9d75eed

36531814751981 has 2 divisors, whose sum is σ = 36531814751982. Its totient is φ = 36531814751980.

The previous prime is 36531814751977. The next prime is 36531814751983. The reversal of 36531814751981 is 18915741813563.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29128245849481 + 7403568902500 = 5397059^2 + 2720950^2 .

It is a cyclic number.

It is not a de Polignac number, because 36531814751981 - 22 = 36531814751977 is a prime.

It is a super-2 number, since 2×365318147519812 (a number of 28 digits) contains 22 as substring.

Together with 36531814751983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (36531814751983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18265907375990 + 18265907375991.

It is an arithmetic number, because the mean of its divisors is an integer number (18265907375991).

Almost surely, 236531814751981 is an apocalyptic number.

It is an amenable number.

36531814751981 is a deficient number, since it is larger than the sum of its proper divisors (1).

36531814751981 is an equidigital number, since it uses as much as digits as its factorization.

36531814751981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 21772800, while the sum is 62.

The spelling of 36531814751981 in words is "thirty-six trillion, five hundred thirty-one billion, eight hundred fourteen million, seven hundred fifty-one thousand, nine hundred eighty-one".