Base | Representation |
---|---|
bin | 1011000100100110001… |
… | …11110111000000011101 |
3 | 1100100221111120100021012 |
4 | 11202103013313000131 |
5 | 22213102402324432 |
6 | 450433125145005 |
7 | 36325203553622 |
oct | 5422307670035 |
9 | 1310844510235 |
10 | 380425433117 |
11 | 13737926a5a4 |
12 | 6188b85b165 |
13 | 29b4913b3a2 |
14 | 145ac5c2349 |
15 | 9d681b6cb2 |
hex | 58931f701d |
380425433117 has 2 divisors, whose sum is σ = 380425433118. Its totient is φ = 380425433116.
The previous prime is 380425433039. The next prime is 380425433137. The reversal of 380425433117 is 711334524083.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 378980596996 + 1444836121 = 615614^2 + 38011^2 .
It is a cyclic number.
It is not a de Polignac number, because 380425433117 - 28 = 380425432861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (380425433137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 190212716558 + 190212716559.
It is an arithmetic number, because the mean of its divisors is an integer number (190212716559).
Almost surely, 2380425433117 is an apocalyptic number.
It is an amenable number.
380425433117 is a deficient number, since it is larger than the sum of its proper divisors (1).
380425433117 is an equidigital number, since it uses as much as digits as its factorization.
380425433117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 41.
The spelling of 380425433117 in words is "three hundred eighty billion, four hundred twenty-five million, four hundred thirty-three thousand, one hundred seventeen".
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