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383379354408313 is a prime number
BaseRepresentation
bin101011100101011100111011…
…0001110111101010101111001
31212021102201010101022112101001
41113022321312032331111321
5400222241404212031223
63435214013301525001
7143516146540255234
oct12712716616752571
91767381111275331
10383379354408313
1110117a2a898006a
1236bb95a2113761
13135bc69705b003
146a9593454a41b
152e4c89bb429ad
hex15cae763bd579

383379354408313 has 2 divisors, whose sum is σ = 383379354408314. Its totient is φ = 383379354408312.

The previous prime is 383379354408307. The next prime is 383379354408319. The reversal of 383379354408313 is 313804453973383.

It is a balanced prime because it is at equal distance from previous prime (383379354408307) and next prime (383379354408319).

It can be written as a sum of positive squares in only one way, i.e., 383349301758864 + 30052649449 = 19579308^2 + 173357^2 .

It is a cyclic number.

It is not a de Polignac number, because 383379354408313 - 237 = 383241915454841 is a prime.

It is not a weakly prime, because it can be changed into another prime (383379354408319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 191689677204156 + 191689677204157.

It is an arithmetic number, because the mean of its divisors is an integer number (191689677204157).

Almost surely, 2383379354408313 is an apocalyptic number.

It is an amenable number.

383379354408313 is a deficient number, since it is larger than the sum of its proper divisors (1).

383379354408313 is an equidigital number, since it uses as much as digits as its factorization.

383379354408313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 235146240, while the sum is 64.

The spelling of 383379354408313 in words is "three hundred eighty-three trillion, three hundred seventy-nine billion, three hundred fifty-four million, four hundred eight thousand, three hundred thirteen".