Base | Representation |
---|---|
bin | 1011001011010011111… |
… | …10111111110011100100 |
3 | 1100201020201121001022021 |
4 | 11211221332333303210 |
5 | 22242443213230200 |
6 | 452230540112524 |
7 | 36513424636201 |
oct | 5455176776344 |
9 | 1321221531267 |
10 | 384030211300 |
11 | 13895905181a |
12 | 62516b35744 |
13 | 2a2a1c02328 |
14 | 14831256ca8 |
15 | 9ec98be41a |
hex | 5969fbfce4 |
384030211300 has 36 divisors (see below), whose sum is σ = 855868419700. Its totient is φ = 149460405120.
The previous prime is 384030211297. The next prime is 384030211319. The reversal of 384030211300 is 3112030483.
It can be written as a sum of positive squares in 6 ways, for example, as 2906719396 + 381123491904 = 53914^2 + 617352^2 .
It is a super-2 number, since 2×3840302113002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 51892275 + ... + 51899674.
Almost surely, 2384030211300 is an apocalyptic number.
It is an amenable number.
384030211300 is an abundant number, since it is smaller than the sum of its proper divisors (471838208400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
384030211300 is a wasteful number, since it uses less digits than its factorization.
384030211300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103792000 (or 103791993 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 384030211300 its reverse (3112030483), we get a palindrome (387142241783).
The spelling of 384030211300 in words is "three hundred eighty-four billion, thirty million, two hundred eleven thousand, three hundred".
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