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3865382501117 is a prime number
BaseRepresentation
bin111000001111111010110…
…000000011101011111101
3111200112020011010012122012
4320033322300003223331
51001312300410013432
612115422053501005
7546156532101644
oct70177260035375
914615204105565
103865382501117
111260332719265
12525178941765
132206723baa57
14d512a90035b
156a832a98cb2
hex383fac03afd

3865382501117 has 2 divisors, whose sum is σ = 3865382501118. Its totient is φ = 3865382501116.

The previous prime is 3865382501093. The next prime is 3865382501119. The reversal of 3865382501117 is 7111052835683.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2137645760761 + 1727736740356 = 1462069^2 + 1314434^2 .

It is a cyclic number.

It is not a de Polignac number, because 3865382501117 - 218 = 3865382238973 is a prime.

Together with 3865382501119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3865382501119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1932691250558 + 1932691250559.

It is an arithmetic number, because the mean of its divisors is an integer number (1932691250559).

Almost surely, 23865382501117 is an apocalyptic number.

It is an amenable number.

3865382501117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3865382501117 is an equidigital number, since it uses as much as digits as its factorization.

3865382501117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1209600, while the sum is 50.

The spelling of 3865382501117 in words is "three trillion, eight hundred sixty-five billion, three hundred eighty-two million, five hundred one thousand, one hundred seventeen".