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38714607742253 is a prime number
BaseRepresentation
bin10001100110101111100100…
…11100010010110100101101
312002002002011120121202022012
420303113302130102310231
520033300004040223003
6214201124551131005
711104016033114012
oct1063276234226455
9162062146552265
1038714607742253
1111376855867943
124413197973a65
13187aa05988ac1
1497bb23007709
154720c84768d8
hex2335f2712d2d

38714607742253 has 2 divisors, whose sum is σ = 38714607742254. Its totient is φ = 38714607742252.

The previous prime is 38714607742211. The next prime is 38714607742271. The reversal of 38714607742253 is 35224770641783.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36514924246564 + 2199683495689 = 6042758^2 + 1483133^2 .

It is an emirp because it is prime and its reverse (35224770641783) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 38714607742253 - 232 = 38710312774957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 38714607742192 and 38714607742201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38714607747253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19357303871126 + 19357303871127.

It is an arithmetic number, because the mean of its divisors is an integer number (19357303871127).

Almost surely, 238714607742253 is an apocalyptic number.

It is an amenable number.

38714607742253 is a deficient number, since it is larger than the sum of its proper divisors (1).

38714607742253 is an equidigital number, since it uses as much as digits as its factorization.

38714607742253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 47416320, while the sum is 59.

The spelling of 38714607742253 in words is "thirty-eight trillion, seven hundred fourteen billion, six hundred seven million, seven hundred forty-two thousand, two hundred fifty-three".