3907750500131 has 2 divisors, whose sum is σ = 3907750500132. Its totient is φ = 3907750500130.

The previous prime is 3907750500091. The next prime is 3907750500133. The reversal of 3907750500131 is 1310050577093.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3907750500131 is a prime.

It is a super-2 number, since 2×3907750500131² (a number of 26 digits) contains 22 as substring.

Together with 3907750500133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3907750500133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1953875250065 + 1953875250066.

It is an arithmetic number, because the mean of its divisors is an integer number (1953875250066).

Almost surely, 2^{3907750500131} is an apocalyptic number.

3907750500131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3907750500131 is an equidigital number, since it uses as much as digits as its factorization.

3907750500131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 99225, while the sum is 41.

The spelling of 3907750500131 in words is "three trillion, nine hundred seven billion, seven hundred fifty million, five hundred thousand, one hundred thirty-one".