Base | Representation |
---|---|
bin | 111000110111011000000… |
… | …101001001011100100101 |
3 | 111211120120211222120002221 |
4 | 320313120011021130211 |
5 | 1003011033112001013 |
6 | 12151110143032341 |
7 | 552216462124654 |
oct | 70673005113445 |
9 | 14746524876087 |
10 | 3907750500133 |
11 | 12772a4311a87 |
12 | 53142189b6b1 |
13 | 224664c3325c |
14 | d71c979b19b |
15 | 6b9b23d508d |
hex | 38dd8149725 |
3907750500133 has 2 divisors, whose sum is σ = 3907750500134. Its totient is φ = 3907750500132.
The previous prime is 3907750500131. The next prime is 3907750500229. The reversal of 3907750500133 is 3310050577093.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3741350142049 + 166400358084 = 1934257^2 + 407922^2 .
It is a cyclic number.
It is not a de Polignac number, because 3907750500133 - 21 = 3907750500131 is a prime.
Together with 3907750500131, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 3907750500133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3907750500131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1953875250066 + 1953875250067.
It is an arithmetic number, because the mean of its divisors is an integer number (1953875250067).
Almost surely, 23907750500133 is an apocalyptic number.
It is an amenable number.
3907750500133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3907750500133 is an equidigital number, since it uses as much as digits as its factorization.
3907750500133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 297675, while the sum is 43.
The spelling of 3907750500133 in words is "three trillion, nine hundred seven billion, seven hundred fifty million, five hundred thousand, one hundred thirty-three".
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