Base | Representation |
---|---|
bin | 111000111101111000101… |
… | …101100000001101010101 |
3 | 111212020121222201022110112 |
4 | 320331320231200031111 |
5 | 1003114342020312411 |
6 | 12154223520532405 |
7 | 552554626242434 |
oct | 70757055401525 |
9 | 14766558638415 |
10 | 3914740400981 |
11 | 127a260998a43 |
12 | 532852781105 |
13 | 22520a111467 |
14 | d768dc4911b |
15 | 6bc70da6b8b |
hex | 38f78b60355 |
3914740400981 has 2 divisors, whose sum is σ = 3914740400982. Its totient is φ = 3914740400980.
The previous prime is 3914740400971. The next prime is 3914740401001. The reversal of 3914740400981 is 1890040474193.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3635180758225 + 279559642756 = 1906615^2 + 528734^2 .
It is a cyclic number.
It is not a de Polignac number, because 3914740400981 - 210 = 3914740399957 is a prime.
It is a super-2 number, since 2×39147404009812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3914740400951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957370200490 + 1957370200491.
It is an arithmetic number, because the mean of its divisors is an integer number (1957370200491).
Almost surely, 23914740400981 is an apocalyptic number.
It is an amenable number.
3914740400981 is a deficient number, since it is larger than the sum of its proper divisors (1).
3914740400981 is an equidigital number, since it uses as much as digits as its factorization.
3914740400981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 50.
The spelling of 3914740400981 in words is "three trillion, nine hundred fourteen billion, seven hundred forty million, four hundred thousand, nine hundred eighty-one".
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