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3914740400981 is a prime number
BaseRepresentation
bin111000111101111000101…
…101100000001101010101
3111212020121222201022110112
4320331320231200031111
51003114342020312411
612154223520532405
7552554626242434
oct70757055401525
914766558638415
103914740400981
11127a260998a43
12532852781105
1322520a111467
14d768dc4911b
156bc70da6b8b
hex38f78b60355

3914740400981 has 2 divisors, whose sum is σ = 3914740400982. Its totient is φ = 3914740400980.

The previous prime is 3914740400971. The next prime is 3914740401001. The reversal of 3914740400981 is 1890040474193.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3635180758225 + 279559642756 = 1906615^2 + 528734^2 .

It is a cyclic number.

It is not a de Polignac number, because 3914740400981 - 210 = 3914740399957 is a prime.

It is a super-2 number, since 2×39147404009812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3914740400951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957370200490 + 1957370200491.

It is an arithmetic number, because the mean of its divisors is an integer number (1957370200491).

Almost surely, 23914740400981 is an apocalyptic number.

It is an amenable number.

3914740400981 is a deficient number, since it is larger than the sum of its proper divisors (1).

3914740400981 is an equidigital number, since it uses as much as digits as its factorization.

3914740400981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 870912, while the sum is 50.

The spelling of 3914740400981 in words is "three trillion, nine hundred fourteen billion, seven hundred forty million, four hundred thousand, nine hundred eighty-one".