Base | Representation |
---|---|
bin | 111000111101111000101… |
… | …101100000001101101001 |
3 | 111212020121222201022111021 |
4 | 320331320231200031221 |
5 | 1003114342020313001 |
6 | 12154223520532441 |
7 | 552554626242463 |
oct | 70757055401551 |
9 | 14766558638437 |
10 | 3914740401001 |
11 | 127a260998a61 |
12 | 532852781121 |
13 | 22520a111481 |
14 | d768dc49133 |
15 | 6bc70da6ba1 |
hex | 38f78b60369 |
3914740401001 has 2 divisors, whose sum is σ = 3914740401002. Its totient is φ = 3914740401000.
The previous prime is 3914740400981. The next prime is 3914740401017. The reversal of 3914740401001 is 1001040474193.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2829716094976 + 1085024306025 = 1682176^2 + 1041645^2 .
It is a cyclic number.
It is not a de Polignac number, because 3914740401001 - 217 = 3914740269929 is a prime.
It is not a weakly prime, because it can be changed into another prime (3914740401041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957370200500 + 1957370200501.
It is an arithmetic number, because the mean of its divisors is an integer number (1957370200501).
Almost surely, 23914740401001 is an apocalyptic number.
It is an amenable number.
3914740401001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3914740401001 is an equidigital number, since it uses as much as digits as its factorization.
3914740401001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
Adding to 3914740401001 its reverse (1001040474193), we get a palindrome (4915780875194).
The spelling of 3914740401001 in words is "three trillion, nine hundred fourteen billion, seven hundred forty million, four hundred one thousand, one".
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