3916650141137 has 2 divisors, whose sum is σ = 3916650141138. Its totient is φ = 3916650141136.

The previous prime is 3916650141113. The next prime is 3916650141139. The reversal of 3916650141137 is 7311410566193.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3662997898816 + 253652242321 = 1913896^2 + 503639^2 .

It is a cyclic number.

It is not a de Polignac number, because 3916650141137 - 2¹⁶ = 3916650075601 is a prime.

Together with 3916650141139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3916650141091 and 3916650141100.

It is not a weakly prime, because it can be changed into another prime (3916650141139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1958325070568 + 1958325070569.

It is an arithmetic number, because the mean of its divisors is an integer number (1958325070569).

Almost surely, 2^{3916650141137} is an apocalyptic number.

It is an amenable number.

3916650141137 is a deficient number, since it is larger than the sum of its proper divisors (1).

3916650141137 is an equidigital number, since it uses as much as digits as its factorization.

3916650141137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 408240, while the sum is 47.

The spelling of 3916650141137 in words is "three trillion, nine hundred sixteen billion, six hundred fifty million, one hundred forty-one thousand, one hundred thirty-seven".