3919104000000 has 1680 divisors, whose sum is σ = 16792872548480. Its totient is φ = 895795200000.

The previous prime is 3919103999981. The next prime is 3919104000011. The reversal of 3919104000000 is 4019193.

It is a tau number, because it is divible by the number of its divisors (1680).

It is a super-4 number, since 4×3919104000000⁴ (a number of 51 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 559871999997 + ... + 559872000003.

Almost surely, 2^{3919104000000} is an apocalyptic number.

3919104000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3919104000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (8396436274240).

3919104000000 is an abundant number, since it is smaller than the sum of its proper divisors (12873768548480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3919104000000 is an frugal number, since it uses more digits than its factorization.

3919104000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86 (or 17 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 27.

Adding to 3919104000000 its reverse (4019193), we get a palindrome (3919108019193).

The spelling of 3919104000000 in words is "three trillion, nine hundred nineteen billion, one hundred four million", and thus it is an aban number.