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3920112031331 is a prime number
BaseRepresentation
bin111001000010111000111…
…000101001011001100011
3111212202111100101102000202
4321002320320221121203
51003211342140000311
612200512525335415
7553135013323346
oct71027070513143
914782440342022
103920112031331
111281568054371
125338b170756b
13225884c5a762
14d7a3d40845d
156be8776ae3b
hex390b8e29663

3920112031331 has 2 divisors, whose sum is σ = 3920112031332. Its totient is φ = 3920112031330.

The previous prime is 3920112031223. The next prime is 3920112031333. The reversal of 3920112031331 is 1331302110293.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1331302110293) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3920112031331 - 226 = 3920044922467 is a prime.

It is a super-2 number, since 2×39201120313312 (a number of 26 digits) contains 22 as substring.

Together with 3920112031333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3920112031294 and 3920112031303.

It is not a weakly prime, because it can be changed into another prime (3920112031333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1960056015665 + 1960056015666.

It is an arithmetic number, because the mean of its divisors is an integer number (1960056015666).

Almost surely, 23920112031331 is an apocalyptic number.

3920112031331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3920112031331 is an equidigital number, since it uses as much as digits as its factorization.

3920112031331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 29.

The spelling of 3920112031331 in words is "three trillion, nine hundred twenty billion, one hundred twelve million, thirty-one thousand, three hundred thirty-one".