Search a number
-
+
3921346497113 is a prime number
BaseRepresentation
bin111001000100000010011…
…101110000101001011001
3111212212200101020202201122
4321010002131300221121
51003221404200401423
612201235224255025
7553210423160063
oct71040235605131
914785611222648
103921346497113
111282040960821
12533b97011475
13225a2092b796
14d7b1934a733
156c00ad138c8
hex39102770a59

3921346497113 has 2 divisors, whose sum is σ = 3921346497114. Its totient is φ = 3921346497112.

The previous prime is 3921346497067. The next prime is 3921346497127. The reversal of 3921346497113 is 3117946431293.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2762337072784 + 1159009424329 = 1662028^2 + 1076573^2 .

It is a cyclic number.

It is not a de Polignac number, because 3921346497113 - 28 = 3921346496857 is a prime.

It is not a weakly prime, because it can be changed into another prime (3921346497163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1960673248556 + 1960673248557.

It is an arithmetic number, because the mean of its divisors is an integer number (1960673248557).

Almost surely, 23921346497113 is an apocalyptic number.

It is an amenable number.

3921346497113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3921346497113 is an equidigital number, since it uses as much as digits as its factorization.

3921346497113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2939328, while the sum is 53.

The spelling of 3921346497113 in words is "three trillion, nine hundred twenty-one billion, three hundred forty-six million, four hundred ninety-seven thousand, one hundred thirteen".