39480500113 has 2 divisors, whose sum is σ = 39480500114. Its totient is φ = 39480500112.

The previous prime is 39480500057. The next prime is 39480500119. The reversal of 39480500113 is 31100508493.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39480497809 + 2304 = 198697^2 + 48^2 .

It is an emirp because it is prime and its reverse (31100508493) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-39480500113 is a prime.

It is not a weakly prime, because it can be changed into another prime (39480500119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19740250056 + 19740250057.

It is an arithmetic number, because the mean of its divisors is an integer number (19740250057).

Almost surely, 2^39480500113 is an apocalyptic number.

It is an amenable number.

39480500113 is a deficient number, since it is larger than the sum of its proper divisors (1).

39480500113 is an equidigital number, since it uses as much as digits as its factorization.

39480500113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 39480500113 in words is "thirty-nine billion, four hundred eighty million, five hundred thousand, one hundred thirteen".