Base | Representation |
---|---|
bin | 11100111101101111… |
… | …000001100101001101 |
3 | 2222021110002112012221 |
4 | 130331233001211031 |
5 | 1002143212232433 |
6 | 22142023455341 |
7 | 2150461650265 |
oct | 347557014515 |
9 | 88243075187 |
10 | 31100508493 |
11 | 1220a47638a |
12 | 603b5b7551 |
13 | 2c18393362 |
14 | 171067a7a5 |
15 | c2056072d |
hex | 73dbc194d |
31100508493 has 2 divisors, whose sum is σ = 31100508494. Its totient is φ = 31100508492.
The previous prime is 31100508469. The next prime is 31100508497. The reversal of 31100508493 is 39480500113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22381057609 + 8719450884 = 149603^2 + 93378^2 .
It is an emirp because it is prime and its reverse (39480500113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31100508493 - 29 = 31100507981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31100508497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550254246 + 15550254247.
It is an arithmetic number, because the mean of its divisors is an integer number (15550254247).
Almost surely, 231100508493 is an apocalyptic number.
It is an amenable number.
31100508493 is a deficient number, since it is larger than the sum of its proper divisors (1).
31100508493 is an equidigital number, since it uses as much as digits as its factorization.
31100508493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 31100508493 in words is "thirty-one billion, one hundred million, five hundred eight thousand, four hundred ninety-three".
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