Base | Representation |
---|---|
bin | 111001110100000110011… |
… | …101110000111011111111 |
3 | 112001210212221101122112222 |
4 | 321310012131300323333 |
5 | 1010043102010332334 |
6 | 12241052143315555 |
7 | 560015325061526 |
oct | 71640635607377 |
9 | 15053787348488 |
10 | 3972953214719 |
11 | 12a1a13573565 |
12 | 541b99babbbb |
13 | 22a856516a88 |
14 | da4131dd4bd |
15 | 6d52b782d2e |
hex | 39d06770eff |
3972953214719 has 2 divisors, whose sum is σ = 3972953214720. Its totient is φ = 3972953214718.
The previous prime is 3972953214697. The next prime is 3972953214721. The reversal of 3972953214719 is 9174123592793.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3972953214719 - 212 = 3972953210623 is a prime.
It is a super-2 number, since 2×39729532147192 (a number of 26 digits) contains 22 as substring.
Together with 3972953214721, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3972953244719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1986476607359 + 1986476607360.
It is an arithmetic number, because the mean of its divisors is an integer number (1986476607360).
Almost surely, 23972953214719 is an apocalyptic number.
3972953214719 is a deficient number, since it is larger than the sum of its proper divisors (1).
3972953214719 is an equidigital number, since it uses as much as digits as its factorization.
3972953214719 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25719120, while the sum is 62.
The spelling of 3972953214719 in words is "three trillion, nine hundred seventy-two billion, nine hundred fifty-three million, two hundred fourteen thousand, seven hundred nineteen".
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