Base | Representation |
---|---|
bin | 111001110101000001101… |
… | …100110000010011101111 |
3 | 112001220110012101011201222 |
4 | 321311001230300103233 |
5 | 1010102120413000142 |
6 | 12241334523453555 |
7 | 560052053110043 |
oct | 71650154602357 |
9 | 15056405334658 |
10 | 3973947000047 |
11 | 12a2383532152 |
12 | 5422169872bb |
13 | 22a98438932b |
14 | da4a91b0023 |
15 | 6d588b37bd2 |
hex | 39d41b304ef |
3973947000047 has 2 divisors, whose sum is σ = 3973947000048. Its totient is φ = 3973947000046.
The previous prime is 3973947000031. The next prime is 3973947000053. The reversal of 3973947000047 is 7400007493793.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3973947000047 - 24 = 3973947000031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3973947000007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1986973500023 + 1986973500024.
It is an arithmetic number, because the mean of its divisors is an integer number (1986973500024).
Almost surely, 23973947000047 is an apocalyptic number.
3973947000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
3973947000047 is an equidigital number, since it uses as much as digits as its factorization.
3973947000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000752, while the sum is 53.
The spelling of 3973947000047 in words is "three trillion, nine hundred seventy-three billion, nine hundred forty-seven million, forty-seven", and thus it is an aban number.
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