Base | Representation |
---|---|
bin | 111010000101010100011… |
… | …010111100001010100111 |
3 | 112010120121101100201222102 |
4 | 322011110122330022213 |
5 | 1010343432341410221 |
6 | 12253350452122315 |
7 | 561241425265121 |
oct | 72052432741247 |
9 | 15116541321872 |
10 | 3991440966311 |
11 | 12a9840406a07 |
12 | 54569960639b |
13 | 22c511801366 |
14 | db288714211 |
15 | 6dc5e88530b |
hex | 3a1546bc2a7 |
3991440966311 has 2 divisors, whose sum is σ = 3991440966312. Its totient is φ = 3991440966310.
The previous prime is 3991440966299. The next prime is 3991440966347. The reversal of 3991440966311 is 1136690441993.
It is a happy number.
3991440966311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1136690441993) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3991440966311 - 210 = 3991440965287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3991440966391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1995720483155 + 1995720483156.
It is an arithmetic number, because the mean of its divisors is an integer number (1995720483156).
Almost surely, 23991440966311 is an apocalyptic number.
3991440966311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3991440966311 is an equidigital number, since it uses as much as digits as its factorization.
3991440966311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3779136, while the sum is 56.
The spelling of 3991440966311 in words is "three trillion, nine hundred ninety-one billion, four hundred forty million, nine hundred sixty-six thousand, three hundred eleven".
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