400044234314441 has 2 divisors, whose sum is σ = 400044234314442. Its totient is φ = 400044234314440.

The previous prime is 400044234314437. The next prime is 400044234314443. The reversal of 400044234314441 is 144413432440004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 250651305744841 + 149392928569600 = 15831971^2 + 12222640^2 .

It is a cyclic number.

It is not a de Polignac number, because 400044234314441 - 2² = 400044234314437 is a prime.

It is a super-2 number, since 2×400044234314441² (a number of 30 digits) contains 22 as substring.

Together with 400044234314443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 400044234314395 and 400044234314404.

It is not a weakly prime, because it can be changed into another prime (400044234314443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200022117157220 + 200022117157221.

It is an arithmetic number, because the mean of its divisors is an integer number (200022117157221).

Almost surely, 2^{400044234314441} is an apocalyptic number.

It is an amenable number.

400044234314441 is a deficient number, since it is larger than the sum of its proper divisors (1).

400044234314441 is an equidigital number, since it uses as much as digits as its factorization.

400044234314441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 294912, while the sum is 38.

Adding to 400044234314441 its reverse (144413432440004), we get a palindrome (544457666754445).

The spelling of 400044234314441 in words is "four hundred trillion, forty-four billion, two hundred thirty-four million, three hundred fourteen thousand, four hundred forty-one".