Base | Representation |
---|---|
bin | 10010001100011110100000… |
… | …00100001001100111100111 |
3 | 12020200000200010102221101102 |
4 | 21012033100010021213213 |
5 | 20221020223421024033 |
6 | 221032503425550315 |
7 | 11266464426656534 |
oct | 1106172004114747 |
9 | 166600603387342 |
10 | 40011111111143 |
11 | 11826687153357 |
12 | 45a25081a539b |
13 | 1943054526143 |
14 | 9c479602dd8b |
15 | 495baa407de8 |
hex | 2463d01099e7 |
40011111111143 has 2 divisors, whose sum is σ = 40011111111144. Its totient is φ = 40011111111142.
The previous prime is 40011111111001. The next prime is 40011111111163. The reversal of 40011111111143 is 34111111111004.
It is an a-pointer prime, because the next prime (40011111111163) can be obtained adding 40011111111143 to its sum of digits (20).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40011111111143 - 222 = 40011106916839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40011111111163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20005555555571 + 20005555555572.
It is an arithmetic number, because the mean of its divisors is an integer number (20005555555572).
Almost surely, 240011111111143 is an apocalyptic number.
40011111111143 is a deficient number, since it is larger than the sum of its proper divisors (1).
40011111111143 is an equidigital number, since it uses as much as digits as its factorization.
40011111111143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 40011111111143 its reverse (34111111111004), we get a palindrome (74122222222147).
The spelling of 40011111111143 in words is "forty trillion, eleven billion, one hundred eleven million, one hundred eleven thousand, one hundred forty-three".
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