Base | Representation |
---|---|
bin | 10010001100100010001110… |
… | …01101011011010011100111 |
3 | 12020200012211102202121202002 |
4 | 21012101013031123103213 |
5 | 20221033322132002331 |
6 | 221033434033435515 |
7 | 11266565111344124 |
oct | 1106210715332347 |
9 | 166605742677662 |
10 | 40013110031591 |
11 | 11827512522924 |
12 | 45a298570bb9b |
13 | 19432b26b2cc8 |
14 | 9c49056c774b |
15 | 495c75b559cb |
hex | 24644735b4e7 |
40013110031591 has 2 divisors, whose sum is σ = 40013110031592. Its totient is φ = 40013110031590.
The previous prime is 40013110031567. The next prime is 40013110031623. The reversal of 40013110031591 is 19513001131004.
40013110031591 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40013110031591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40013110031551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20006555015795 + 20006555015796.
It is an arithmetic number, because the mean of its divisors is an integer number (20006555015796).
Almost surely, 240013110031591 is an apocalyptic number.
40013110031591 is a deficient number, since it is larger than the sum of its proper divisors (1).
40013110031591 is an equidigital number, since it uses as much as digits as its factorization.
40013110031591 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 29.
Adding to 40013110031591 its reverse (19513001131004), we get a palindrome (59526111162595).
The spelling of 40013110031591 in words is "forty trillion, thirteen billion, one hundred ten million, thirty-one thousand, five hundred ninety-one".
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