Base | Representation |
---|---|
bin | 10010001100100010001110… |
… | …01101011011010010111111 |
3 | 12020200012211102202121200121 |
4 | 21012101013031123102333 |
5 | 20221033322132002201 |
6 | 221033434033435411 |
7 | 11266565111344036 |
oct | 1106210715332277 |
9 | 166605742677617 |
10 | 40013110031551 |
11 | 11827512522898 |
12 | 45a298570bb67 |
13 | 19432b26b2c97 |
14 | 9c49056c771d |
15 | 495c75b559a1 |
hex | 24644735b4bf |
40013110031551 has 2 divisors, whose sum is σ = 40013110031552. Its totient is φ = 40013110031550.
The previous prime is 40013110031539. The next prime is 40013110031567. The reversal of 40013110031551 is 15513001131004.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40013110031551 - 221 = 40013107934399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40013110031591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20006555015775 + 20006555015776.
It is an arithmetic number, because the mean of its divisors is an integer number (20006555015776).
Almost surely, 240013110031551 is an apocalyptic number.
40013110031551 is a deficient number, since it is larger than the sum of its proper divisors (1).
40013110031551 is an equidigital number, since it uses as much as digits as its factorization.
40013110031551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 40013110031551 its reverse (15513001131004), we get a palindrome (55526111162555).
The spelling of 40013110031551 in words is "forty trillion, thirteen billion, one hundred ten million, thirty-one thousand, five hundred fifty-one".
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