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40110141312149 is a prime number
BaseRepresentation
bin10010001111010110111101…
…01110011000110010010101
312021000111021201020101111212
421013223132232120302111
520224131032133442044
6221150202230511205
711306601456540656
oct1107533656306225
9167014251211455
1040110141312149
1111864685113087
1245b9745205505
13194c4a714100c
149c94ac36552d
15498554429a9e
hex247adeb98c95

40110141312149 has 2 divisors, whose sum is σ = 40110141312150. Its totient is φ = 40110141312148.

The previous prime is 40110141312119. The next prime is 40110141312203. The reversal of 40110141312149 is 94121314101104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22617462431524 + 17492678880625 = 4755782^2 + 4182425^2 .

It is a cyclic number.

It is not a de Polignac number, because 40110141312149 - 232 = 40105846344853 is a prime.

It is a super-3 number, since 3×401101413121493 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40110141312119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20055070656074 + 20055070656075.

It is an arithmetic number, because the mean of its divisors is an integer number (20055070656075).

Almost surely, 240110141312149 is an apocalyptic number.

It is an amenable number.

40110141312149 is a deficient number, since it is larger than the sum of its proper divisors (1).

40110141312149 is an equidigital number, since it uses as much as digits as its factorization.

40110141312149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 32.

The spelling of 40110141312149 in words is "forty trillion, one hundred ten billion, one hundred forty-one million, three hundred twelve thousand, one hundred forty-nine".