Base | Representation |
---|---|
bin | 111010010111101110110… |
… | …011110100010111100111 |
3 | 112012110122012020222011211 |
4 | 322113232303310113213 |
5 | 1011204430012022143 |
6 | 12310420325412251 |
7 | 562541356230355 |
oct | 72275663642747 |
9 | 15173565228154 |
10 | 4011211048423 |
11 | 1307166079247 |
12 | 54949656a087 |
13 | 2313426781b7 |
14 | dc20226a7d5 |
15 | 6e51a33749d |
hex | 3a5eecf45e7 |
4011211048423 has 2 divisors, whose sum is σ = 4011211048424. Its totient is φ = 4011211048422.
The previous prime is 4011211048409. The next prime is 4011211048477. The reversal of 4011211048423 is 3248401121104.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4011211048423 - 213 = 4011211040231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4011211048123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005605524211 + 2005605524212.
It is an arithmetic number, because the mean of its divisors is an integer number (2005605524212).
Almost surely, 24011211048423 is an apocalyptic number.
4011211048423 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011211048423 is an equidigital number, since it uses as much as digits as its factorization.
4011211048423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 4011211048423 its reverse (3248401121104), we get a palindrome (7259612169527).
The spelling of 4011211048423 in words is "four trillion, eleven billion, two hundred eleven million, forty-eight thousand, four hundred twenty-three".
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