Base | Representation |
---|---|
bin | 111010010111110110000… |
… | …001101110000010110000 |
3 | 112012110221122002201001021 |
4 | 322113312001232002300 |
5 | 1011210202011224130 |
6 | 12310440332545224 |
7 | 562544356356631 |
oct | 72276601560260 |
9 | 15173848081037 |
10 | 4011332133040 |
11 | 1307218460981 |
12 | 54950b022214 |
13 | 2313617919bb |
14 | dc214389888 |
15 | 6e525ca437a |
hex | 3a5f606e0b0 |
4011332133040 has 40 divisors (see below), whose sum is σ = 9326657752128. Its totient is φ = 1604479426560.
The previous prime is 4011332133023. The next prime is 4011332133047. The reversal of 4011332133040 is 403312331104.
It is a tau number, because it is divible by the number of its divisors (40).
It is a junction number, because it is equal to n+sod(n) for n = 4011332132996 and 4011332133014.
It is not an unprimeable number, because it can be changed into a prime (4011332133047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1627945 + ... + 3266935.
Almost surely, 24011332133040 is an apocalyptic number.
4011332133040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
4011332133040 is an abundant number, since it is smaller than the sum of its proper divisors (5315325619088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4011332133040 is a wasteful number, since it uses less digits than its factorization.
4011332133040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1669597 (or 1669591 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 4011332133040 its reverse (403312331104), we get a palindrome (4414644464144).
The spelling of 4011332133040 in words is "four trillion, eleven billion, three hundred thirty-two million, one hundred thirty-three thousand, forty".
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