Search a number
-
+
401200117 is a prime number
BaseRepresentation
bin10111111010011…
…101001111110101
31000221221002002121
4113322131033311
51310201400432
6103451035541
712641100433
oct2772351765
91027832077
10401200117
1119651564a
12b243bbb1
1365171926
143b3d7d53
152534e197
hex17e9d3f5

401200117 has 2 divisors, whose sum is σ = 401200118. Its totient is φ = 401200116.

The previous prime is 401200103. The next prime is 401200133. The reversal of 401200117 is 711002104.

It is an a-pointer prime, because the next prime (401200133) can be obtained adding 401200117 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 245674276 + 155525841 = 15674^2 + 12471^2 .

It is a cyclic number.

It is not a de Polignac number, because 401200117 - 211 = 401198069 is a prime.

It is a super-3 number, since 3×4012001173 (a number of 27 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 401200117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401200147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200600058 + 200600059.

It is an arithmetic number, because the mean of its divisors is an integer number (200600059).

Almost surely, 2401200117 is an apocalyptic number.

It is an amenable number.

401200117 is a deficient number, since it is larger than the sum of its proper divisors (1).

401200117 is an equidigital number, since it uses as much as digits as its factorization.

401200117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 16.

The square root of 401200117 is about 20029.9804543090. The cubic root of 401200117 is about 737.5424421424.

The spelling of 401200117 in words is "four hundred one million, two hundred thousand, one hundred seventeen".