Base | Representation |
---|---|
bin | 111010011000100101101… |
… | …001101010000000010101 |
3 | 112012120000022120000202121 |
4 | 322120211221222000111 |
5 | 1011213321032201123 |
6 | 12311051514135541 |
7 | 562603230632146 |
oct | 72304551520025 |
9 | 15176008500677 |
10 | 4012131131413 |
11 | 1307598478209 |
12 | 5496b27215b1 |
13 | 23145b1839c2 |
14 | dc28c533acd |
15 | 6e570ece75d |
hex | 3a625a6a015 |
4012131131413 has 2 divisors, whose sum is σ = 4012131131414. Its totient is φ = 4012131131412.
The previous prime is 4012131131339. The next prime is 4012131131417. The reversal of 4012131131413 is 3141311312104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3156741065284 + 855390066129 = 1776722^2 + 924873^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4012131131413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4012131131417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006065565706 + 2006065565707.
It is an arithmetic number, because the mean of its divisors is an integer number (2006065565707).
Almost surely, 24012131131413 is an apocalyptic number.
It is an amenable number.
4012131131413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012131131413 is an equidigital number, since it uses as much as digits as its factorization.
4012131131413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 4012131131413 its reverse (3141311312104), we get a palindrome (7153442443517).
The spelling of 4012131131413 in words is "four trillion, twelve billion, one hundred thirty-one million, one hundred thirty-one thousand, four hundred thirteen".
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