401214131 has 2 divisors, whose sum is σ = 401214132. Its totient is φ = 401214130.

The previous prime is 401214119. The next prime is 401214167. The reversal of 401214131 is 131412104.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 401214131 - 2¹⁴ = 401197747 is a prime.

It is a super-2 number, since 2×401214131² = 321945557828170322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (401214181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200607065 + 200607066.

It is an arithmetic number, because the mean of its divisors is an integer number (200607066).

Almost surely, 2^401214131 is an apocalyptic number.

401214131 is a deficient number, since it is larger than the sum of its proper divisors (1).

401214131 is an equidigital number, since it uses as much as digits as its factorization.

401214131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 401214131 is about 20030.3302768576. The cubic root of 401214131 is about 737.5510295438.

Adding to 401214131 its reverse (131412104), we get a palindrome (532626235).

The spelling of 401214131 in words is "four hundred one million, two hundred fourteen thousand, one hundred thirty-one".