Base | Representation |
---|---|
bin | 10010001111110001100001… |
… | …01100011000101111111111 |
3 | 12021001212002112010222210001 |
4 | 21013320300230120233333 |
5 | 20224344233230440221 |
6 | 221200521234255131 |
7 | 11310615033504154 |
oct | 1107706054305777 |
9 | 167055075128701 |
10 | 40124401421311 |
11 | 1186a73261a169 |
12 | 4600464a274a7 |
13 | 195093a5c1a2c |
14 | 9ca0621ca22b |
15 | 498adb2dc391 |
hex | 247e30b18bff |
40124401421311 has 2 divisors, whose sum is σ = 40124401421312. Its totient is φ = 40124401421310.
The previous prime is 40124401421303. The next prime is 40124401421317. The reversal of 40124401421311 is 11312410442104.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40124401421311 - 23 = 40124401421303 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40124401421311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40124401421317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20062200710655 + 20062200710656.
It is an arithmetic number, because the mean of its divisors is an integer number (20062200710656).
Almost surely, 240124401421311 is an apocalyptic number.
40124401421311 is a deficient number, since it is larger than the sum of its proper divisors (1).
40124401421311 is an equidigital number, since it uses as much as digits as its factorization.
40124401421311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 40124401421311 its reverse (11312410442104), we get a palindrome (51436811863415).
The spelling of 40124401421311 in words is "forty trillion, one hundred twenty-four billion, four hundred one million, four hundred twenty-one thousand, three hundred eleven".
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