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401254151 is a prime number
BaseRepresentation
bin10111111010101…
…010011100000111
31000222000211012212
4113322222130013
51310210113101
6103452134035
712641414114
oct2772523407
91028024185
10401254151
11196552201
12b246731b
13651903bc
143b40d90b
15253601bb
hex17eaa707

401254151 has 2 divisors, whose sum is σ = 401254152. Its totient is φ = 401254150.

The previous prime is 401254129. The next prime is 401254153. The reversal of 401254151 is 151452104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401254151 - 222 = 397059847 is a prime.

It is a super-2 number, since 2×4012541512 = 322009787389461602, which contains 22 as substring.

Together with 401254153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401254153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200627075 + 200627076.

It is an arithmetic number, because the mean of its divisors is an integer number (200627076).

Almost surely, 2401254151 is an apocalyptic number.

401254151 is a deficient number, since it is larger than the sum of its proper divisors (1).

401254151 is an equidigital number, since it uses as much as digits as its factorization.

401254151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 800, while the sum is 23.

The square root of 401254151 is about 20031.3292369728. The cubic root of 401254151 is about 737.5755516203.

The spelling of 401254151 in words is "four hundred one million, two hundred fifty-four thousand, one hundred fifty-one".