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4012552772087 is a prime number
BaseRepresentation
bin111010011000111110110…
…010000101100111110111
3112012121002200221121000212
4322120332302011213313
51011220202002201322
612311201415300035
7562616540545226
oct72307662054767
915177080847025
104012552772087
111307794484082
125497ab97a61b
132314c7631422
14dc2cc52ccbd
156e59801a0e2
hex3a63ec859f7

4012552772087 has 2 divisors, whose sum is σ = 4012552772088. Its totient is φ = 4012552772086.

The previous prime is 4012552772083. The next prime is 4012552772089. The reversal of 4012552772087 is 7802772552104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4012552772087 - 22 = 4012552772083 is a prime.

It is a super-2 number, since 2×40125527720872 (a number of 26 digits) contains 22 as substring.

Together with 4012552772089, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4012552772083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006276386043 + 2006276386044.

It is an arithmetic number, because the mean of its divisors is an integer number (2006276386044).

Almost surely, 24012552772087 is an apocalyptic number.

4012552772087 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012552772087 is an equidigital number, since it uses as much as digits as its factorization.

4012552772087 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2195200, while the sum is 50.

The spelling of 4012552772087 in words is "four trillion, twelve billion, five hundred fifty-two million, seven hundred seventy-two thousand, eighty-seven".