Base | Representation |
---|---|
bin | 111010011001001010110… |
… | …101101111000010010111 |
3 | 112012121121210120121200002 |
4 | 322121022311233002113 |
5 | 1011221110243222433 |
6 | 12311233443041515 |
7 | 562624545120461 |
oct | 72311265570227 |
9 | 15177553517602 |
10 | 4012755054743 |
11 | 1307888686026 |
12 | 54984767029b |
13 | 23152a5076c6 |
14 | dc30b347131 |
15 | 6e5aab759e8 |
hex | 3a64ad6f097 |
4012755054743 has 2 divisors, whose sum is σ = 4012755054744. Its totient is φ = 4012755054742.
The previous prime is 4012755054709. The next prime is 4012755054751. The reversal of 4012755054743 is 3474505572104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4012755054743 - 216 = 4012754989207 is a prime.
It is a super-3 number, since 3×40127550547433 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4012755054043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006377527371 + 2006377527372.
It is an arithmetic number, because the mean of its divisors is an integer number (2006377527372).
Almost surely, 24012755054743 is an apocalyptic number.
4012755054743 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012755054743 is an equidigital number, since it uses as much as digits as its factorization.
4012755054743 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2352000, while the sum is 47.
The spelling of 4012755054743 in words is "four trillion, twelve billion, seven hundred fifty-five million, fifty-four thousand, seven hundred forty-three".
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