40128471111143 has 2 divisors, whose sum is σ = 40128471111144. Its totient is φ = 40128471111142.

The previous prime is 40128471111119. The next prime is 40128471111161. The reversal of 40128471111143 is 34111117482104.

40128471111143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40128471111143 - 2⁸ = 40128471110887 is a prime.

It is a super-2 number, since 2×40128471111143² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40128471111097 and 40128471111106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40128471111163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20064235555571 + 20064235555572.

It is an arithmetic number, because the mean of its divisors is an integer number (20064235555572).

Almost surely, 2^{40128471111143} is an apocalyptic number.

40128471111143 is a deficient number, since it is larger than the sum of its proper divisors (1).

40128471111143 is an equidigital number, since it uses as much as digits as its factorization.

40128471111143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21504, while the sum is 38.

Adding to 40128471111143 its reverse (34111117482104), we get a palindrome (74239588593247).

The spelling of 40128471111143 in words is "forty trillion, one hundred twenty-eight billion, four hundred seventy-one million, one hundred eleven thousand, one hundred forty-three".