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401291376257 is a prime number
BaseRepresentation
bin1011101011011101101…
…01000111011010000001
31102100210200112002012002
411311232311013122001
523033321043020012
6504203430513345
740664242263242
oct5655665073201
91370720462162
10401291376257
1114520657a502
1265933805855
132bac3046cc5
14155cb8bacc9
15a689e837c2
hex5d6ed47681

401291376257 has 2 divisors, whose sum is σ = 401291376258. Its totient is φ = 401291376256.

The previous prime is 401291376179. The next prime is 401291376259. The reversal of 401291376257 is 752673192104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 389356032256 + 11935344001 = 623984^2 + 109249^2 .

It is a cyclic number.

It is not a de Polignac number, because 401291376257 - 230 = 400217634433 is a prime.

It is a super-2 number, since 2×4012913762572 (a number of 24 digits) contains 22 as substring.

Together with 401291376259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (401291376259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200645688128 + 200645688129.

It is an arithmetic number, because the mean of its divisors is an integer number (200645688129).

Almost surely, 2401291376257 is an apocalyptic number.

It is an amenable number.

401291376257 is a deficient number, since it is larger than the sum of its proper divisors (1).

401291376257 is an equidigital number, since it uses as much as digits as its factorization.

401291376257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 635040, while the sum is 47.

The spelling of 401291376257 in words is "four hundred one billion, two hundred ninety-one million, three hundred seventy-six thousand, two hundred fifty-seven".