401310005533 has 2 divisors, whose sum is σ = 401310005534. Its totient is φ = 401310005532.

The previous prime is 401310005483. The next prime is 401310005687. The reversal of 401310005533 is 335500013104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 371547545209 + 29762460324 = 609547^2 + 172518^2 .

It is a cyclic number.

It is not a de Polignac number, because 401310005533 - 2²⁵ = 401276451101 is a prime.

It is a super-2 number, since 2×401310005533² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401310005498 and 401310005507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401311005533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200655002766 + 200655002767.

It is an arithmetic number, because the mean of its divisors is an integer number (200655002767).

Almost surely, 2^401310005533 is an apocalyptic number.

It is an amenable number.

401310005533 is a deficient number, since it is larger than the sum of its proper divisors (1).

401310005533 is an equidigital number, since it uses as much as digits as its factorization.

401310005533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 401310005533 its reverse (335500013104), we get a palindrome (736810018637).

The spelling of 401310005533 in words is "four hundred one billion, three hundred ten million, five thousand, five hundred thirty-three".