Base | Representation |
---|---|
bin | 111010011001011111100… |
… | …110101100011000011000 |
3 | 112012122112002010002010101 |
4 | 322121133212230120120 |
5 | 1011222313434330430 |
6 | 12311332210025144 |
7 | 562636305232306 |
oct | 72313746543030 |
9 | 15178462102111 |
10 | 4013103433240 |
11 | 1307a472a2a40 |
12 | 5499242781b4 |
13 | 231584743825 |
14 | dc341711276 |
15 | 6e5cb53ddca |
hex | 3a65f9ac618 |
4013103433240 has 32 divisors (see below), whose sum is σ = 9850344791760. Its totient is φ = 1459310339200.
The previous prime is 4013103433237. The next prime is 4013103433277. The reversal of 4013103433240 is 423343013104.
It is a super-2 number, since 2×40131034332402 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4013103433199 and 4013103433208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4560344371 + ... + 4560345250.
Almost surely, 24013103433240 is an apocalyptic number.
4013103433240 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
4013103433240 is an abundant number, since it is smaller than the sum of its proper divisors (5837241358520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4013103433240 is a wasteful number, since it uses less digits than its factorization.
4013103433240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9120689643 (or 9120689639 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 4013103433240 its reverse (423343013104), we get a palindrome (4436446446344).
The spelling of 4013103433240 in words is "four trillion, thirteen billion, one hundred three million, four hundred thirty-three thousand, two hundred forty".
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