Base | Representation |
---|---|
bin | 10010001111111111001100… |
… | …00000001001000111110111 |
3 | 12021002120000211200011211222 |
4 | 21013333212000021013313 |
5 | 20230004244442243300 |
6 | 221204133244020555 |
7 | 11311264612454426 |
oct | 1107774600110767 |
9 | 167076024604758 |
10 | 40131738243575 |
11 | 11872858008340 |
12 | 4601971b3175b |
13 | 1951539618a94 |
14 | 9ca55a7832bd |
15 | 498dba48a785 |
hex | 247fe60091f7 |
40131738243575 has 24 divisors (see below), whose sum is σ = 54289946314800. Its totient is φ = 29185294265600.
The previous prime is 40131738243547. The next prime is 40131738243593. The reversal of 40131738243575 is 57534283713104.
It is not a de Polignac number, because 40131738243575 - 218 = 40131737981431 is a prime.
It is a super-2 number, since 2×401317382435752 (a number of 28 digits) contains 22 as substring.
It is a hoax number, since the sum of its digits (53) coincides with the sum of the digits of its distinct prime factors.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2100107 + ... + 9201843.
It is an arithmetic number, because the mean of its divisors is an integer number (2262081096450).
Almost surely, 240131738243575 is an apocalyptic number.
40131738243575 is a deficient number, since it is larger than the sum of its proper divisors (14158208071225).
40131738243575 is a wasteful number, since it uses less digits than its factorization.
40131738243575 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7122307 (or 7122302 counting only the distinct ones).
The product of its (nonzero) digits is 8467200, while the sum is 53.
The spelling of 40131738243575 in words is "forty trillion, one hundred thirty-one billion, seven hundred thirty-eight million, two hundred forty-three thousand, five hundred seventy-five".
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