40131754823117 has 2 divisors, whose sum is σ = 40131754823118. Its totient is φ = 40131754823116.

The previous prime is 40131754823087. The next prime is 40131754823131. The reversal of 40131754823117 is 71132845713104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40127993331556 + 3761491561 = 6334666^2 + 61331^2 .

It is a cyclic number.

It is not a de Polignac number, because 40131754823117 - 2¹⁶ = 40131754757581 is a prime.

It is a super-2 number, since 2×40131754823117² (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40131754823617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065877411558 + 20065877411559.

It is an arithmetic number, because the mean of its divisors is an integer number (20065877411559).

Almost surely, 2^{40131754823117} is an apocalyptic number.

It is an amenable number.

40131754823117 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131754823117 is an equidigital number, since it uses as much as digits as its factorization.

40131754823117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 564480, while the sum is 47.

The spelling of 40131754823117 in words is "forty trillion, one hundred thirty-one billion, seven hundred fifty-four million, eight hundred twenty-three thousand, one hundred seventeen".