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40132067212949 is a prime number
BaseRepresentation
bin10010001111111111110011…
…00111000011111010010101
312021002120212202200112222212
421013333321213003322111
520230010433201303244
6221204230035003205
711311306015611005
oct1107777147037225
9167076782615885
1040132067212949
1111872a06778958
124601a44139505
13195158c81a70a
149ca58c338005
15498dd92bcd9e
hex247ff99c3e95

40132067212949 has 2 divisors, whose sum is σ = 40132067212950. Its totient is φ = 40132067212948.

The previous prime is 40132067212943. The next prime is 40132067212961. The reversal of 40132067212949 is 94921276023104.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37025484710449 + 3106582502500 = 6084857^2 + 1762550^2 .

It is a cyclic number.

It is not a de Polignac number, because 40132067212949 - 220 = 40132066164373 is a prime.

It is a super-2 number, since 2×401320672129492 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40132067212897 and 40132067212906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132067212943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066033606474 + 20066033606475.

It is an arithmetic number, because the mean of its divisors is an integer number (20066033606475).

Almost surely, 240132067212949 is an apocalyptic number.

It is an amenable number.

40132067212949 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132067212949 is an equidigital number, since it uses as much as digits as its factorization.

40132067212949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 40132067212949 in words is "forty trillion, one hundred thirty-two billion, sixty-seven million, two hundred twelve thousand, nine hundred forty-nine".