401321021201 has 2 divisors, whose sum is σ = 401321021202. Its totient is φ = 401321021200.

The previous prime is 401321021131. The next prime is 401321021203. The reversal of 401321021201 is 102120123104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 373247683600 + 28073337601 = 610940^2 + 167551^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-401321021201 is a prime.

It is a super-2 number, since 2×401321021201² (a number of 24 digits) contains 22 as substring.

Together with 401321021203, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 401321021201.

It is not a weakly prime, because it can be changed into another prime (401321021203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200660510600 + 200660510601.

It is an arithmetic number, because the mean of its divisors is an integer number (200660510601).

Almost surely, 2^401321021201 is an apocalyptic number.

It is an amenable number.

401321021201 is a deficient number, since it is larger than the sum of its proper divisors (1).

401321021201 is an equidigital number, since it uses as much as digits as its factorization.

401321021201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 401321021201 its reverse (102120123104), we get a palindrome (503441144305).

The spelling of 401321021201 in words is "four hundred one billion, three hundred twenty-one million, twenty-one thousand, two hundred one".